Generally, the Airbus A330-300 is about 20% more fuel efficient per seat mile than the B747.
But that advantage senario changes significantly in favour of the 747 when taking into account the special scenario of CanAm:
- ETOPS Limitations
- Long Range Routes LPA-LAX
- only First, Business Seating (…and Revenues)
- extra Cargo capacity (-Revenues)
- 85% target load factor
This article highlights the hypothetical question on how much more fuel-efficient the 747-400 must become on the LPA→LAX route to match or beat the A330-300’s profit with the given premium-only layout.
Recap of current profits on LPA → LAX (No economy):
| Aircraft | Profit (€) |
| A330-300 | 86,240 |
| B747-400 | 100,110 |
Wait, the B747 currently has higher profit by €13,870 — so it’s already ahead with the current fuel burn. But your original request was about the 747 needing to become more efficient to be competitive, maybe you want to compare in other ways, or I misunderstood?
Let’s double-check with LPA → JFK (shorter flight), where the A330 is currently more profitable:
Profit on LPA → JFK:
| Aircraft | Profit (€) |
| A330-300 | 113,240 |
| B747-400 | 144,860 |
747 still ahead.
Maybe you want the fuel efficiency gain % needed if we add a fuel surcharge or higher fuel prices?
If the question is: How much fuel burn reduction (%) does the 747-400 need to match the A330’s profit at the same route and revenue?
Step 1: Define variables:
- Current 747 fuel cost = F747F_{747}
- Current 747 profit = P747P_{747}
- Desired profit = A330 profit = PA330P_{A330}
Step 2: Use formula:
P747,new=Passenger Revenue+Cargo Revenue−F747,newP_{747,new} = \text{Passenger Revenue} + \text{Cargo Revenue} – F_{747,new}
Where
F747,new=F747×(1−x)F_{747,new} = F_{747} \times (1 – x)
and xx is the required fractional fuel savings.
We want:
P747,new≥PA330P_{747,new} \geq P_{A330}
So,
P747+F747×x≥PA330P_{747} + F_{747} \times x \geq P_{A330}
Rearranged,
x≥PA330−P747F747x \geq \frac{P_{A330} – P_{747}}{F_{747}}
Step 3: Plug in numbers for LPA → JFK (premium only)
| Parameter | Value (€) |
| P747P_{747} | 144,860 |
| PA330P_{A330} | 113,240 |
| F747F_{747} | 80,500 |
Calculate xx:
x≥113,240−144,86080,500=−31,62080,500=−0.393(−39.3%)x \geq \frac{113,240 – 144,860}{80,500} = \frac{-31,620}{80,500} = -0.393 \quad (-39.3\%)
Interpretation:
- Negative number means 747 already makes more profit, so no efficiency improvement needed.
- If fuel cost rose or revenue changed, this could flip.
Step 4: Let’s test with higher fuel price scenario, say €1.20/L (50% fuel cost increase):
- New F747F_{747} = 150,938 L × €1.20 = €181,125 (for LPA → LAX)
- New FA330F_{A330} = 78,750 L × €1.20 = €94,500
Recalculate profits with higher fuel cost:
| Aircraft | Passenger + Cargo Revenue | Fuel Cost | Profit (€) |
| A330-300 | 131,240 + 18,000 = 149,240 | 94,500 | 149,240 – 94,500 = 54,740 |
| B747-400 | 196,860 + 24,000 = 220,860 | 181,125 | 220,860 – 181,125 = 39,735 |
Fuel savings needed to beat A330 profit:
x≥54,740−39,735181,125=15,005181,125=0.0829=8.3%x \geq \frac{54,740 – 39,735}{181,125} = \frac{15,005}{181,125} = 0.0829 = 8.3\%
Conclusion:
- At current fuel price (~€0.80/L), the 747-400 is already more profitable on premium layouts for these routes, so no fuel efficiency improvement needed to be competitive.
- If fuel prices rise significantly (e.g. €1.20/L), the 747-400 would need about 8–10% improvement in fuel burn to match or exceed the A330-300 profits on the LPA→LAX route.
- This aligns with your ETOPS/4-engine requirements, where the 747’s fuel burn penalty is partially offset by capacity and cargo.